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(5/3)x=35/3
We move all terms to the left:
(5/3)x-(35/3)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/3)x-(+35/3)=0
We multiply parentheses
5x^2-(+35/3)=0
We get rid of parentheses
5x^2-35/3=0
We multiply all the terms by the denominator
5x^2*3-35=0
Wy multiply elements
15x^2-35=0
a = 15; b = 0; c = -35;
Δ = b2-4ac
Δ = 02-4·15·(-35)
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{21}}{2*15}=\frac{0-10\sqrt{21}}{30} =-\frac{10\sqrt{21}}{30} =-\frac{\sqrt{21}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{21}}{2*15}=\frac{0+10\sqrt{21}}{30} =\frac{10\sqrt{21}}{30} =\frac{\sqrt{21}}{3} $
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