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(5/3)y+4=(2/3)y
We move all terms to the left:
(5/3)y+4-((2/3)y)=0
Domain of the equation: 3)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 3)y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/3)y-((+2/3)y)+4=0
We multiply parentheses
5y^2-((+2/3)y)+4=0
We multiply all the terms by the denominator
5y^2*3)y)-((+4*3)y)+2=0
We add all the numbers together, and all the variables
5y^2*3)y)-(12y)+2=0
We add all the numbers together, and all the variables
5y^2*3)y)-12y+2=0
Wy multiply elements
15y^3=0
We do not support eypression: y^3
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