(5/3x)+5x=(35/3)

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Solution for (5/3x)+5x=(35/3) equation: 



(5/3x)+5x=(35/3)

We move all terms to the left:

(5/3x)+5x-((35/3))=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/3x)+5x-((+35/3))=0

We add all the numbers together, and all the variables

5x+(+5/3x)-((+35/3))=0

We get rid of parentheses

5x+5/3x-((+35/3))=0

We calculate fractions


5x+()/9x^2+(-((+35*3x)/9x^2=0

We multiply all the terms by the denominator


5x*9x^2+(-((+35*3x)+()=0



We calculate terms in parentheses: +(-((+35*3x)+(), so:

-((+35*3x)+(



Wy multiply elements

45x^3+(-((+35*3x)+()=0



We calculate terms in parentheses: +(-((+35*3x)+(), so:

-((+35*3x)+(



We do not support expression: x^3

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