(5/4)b+7=(7/8)b+19

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Solution for (5/4)b+7=(7/8)b+19 equation:



(5/4)b+7=(7/8)b+19
We move all terms to the left:
(5/4)b+7-((7/8)b+19)=0
Domain of the equation: 4)b!=0
b!=0/1
b!=0
b∈R
Domain of the equation: 8)b+19)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
(+5/4)b-((+7/8)b+19)+7=0
We multiply parentheses
5b^2-((+7/8)b+19)+7=0
We multiply all the terms by the denominator
5b^2*8)b+19)-((+7*8)b+19)+7=0
We add all the numbers together, and all the variables
5b^2*8)b+19)-(56b+19)+7=0
Wy multiply elements
40b^3=0
We do not support ebpression: b^3

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