(5/4)b+7=(7/8b+19

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Solution for (5/4)b+7=(7/8b+19 equation: 



(5/4)b+7=(7/8b+19

We move all terms to the left:

(5/4)b+7-((7/8b+19)=0



Domain of the equation: 4)b!=0

b!=0/1

b!=0

b∈R





Domain of the equation: 8b+19)+7!=0

b∈R



We add all the numbers together, and all the variables

(+5/4)b-((7/8b+19)+7=0

We multiply parentheses

5b^2-((7/8b+19)+7=0

We multiply all the terms by the denominator


5b^2*8b+19)+7-((7=0

We add all the numbers together, and all the variables

5b^2*8b=0

Wy multiply elements

40b^3=0

We do not support ebpression: b^3

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