(5/4)x+(2/3)=(-1/6)x+3

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Solution for (5/4)x+(2/3)=(-1/6)x+3 equation: 



(5/4)x+(2/3)=(-1/6)x+3

We move all terms to the left:

(5/4)x+(2/3)-((-1/6)x+3)=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 6)x+3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/4)x-((-1/6)x+3)+(+2/3)=0

We multiply parentheses

5x^2-((-1/6)x+3)+(+2/3)=0

We get rid of parentheses

5x^2-((-1/6)x+3)+2/3=0

We calculate fractions


5x^2+()/6x+3)*3)+12x/6x+3)*3)=0

We calculate fractions


5x^2+(()*6x)/36x^2+3*3)+12x*6x)/36x^2=0

We multiply all the terms by the denominator


5x^2*36x^2+(()*6x)+3*3)+12x*6x)=0



We calculate terms in parentheses: +(()*6x), so:

()*6x



Wy multiply elements

180x^4+54x^2+(()*6x)=0



We calculate terms in parentheses: +(()*6x), so:

()*6x



We do not support expression: x^4

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