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(5/4)x+(7/2)=2x-(5/2)
We move all terms to the left:
(5/4)x+(7/2)-(2x-(5/2))=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/4)x-(2x-(+5/2))+(+7/2)=0
We multiply parentheses
5x^2-(2x-(+5/2))+(+7/2)=0
We get rid of parentheses
5x^2-(2x-(+5/2))+7/2=0
We calculate fractions
5x^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{10}=0$
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