(5/4)x+7=13+x

Solution for (5/4)x+7=13+x equation:

(5/4)x+7=13+x

We move all terms to the left:

(5/4)x+7-(13+x)=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+5/4)x-(x+13)+7=0

We multiply parentheses

5x^2-(x+13)+7=0

We get rid of parentheses

5x^2-x-13+7=0

We add all the numbers together, and all the variables

5x^2-1x-6=0

a = 5; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·5·(-6)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*5}=\frac{-10}{10}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*5}=\frac{12}{10}
=1+1/5
$