(5/4)x=43

Solution for (5/4)x=43 equation:

(5/4)x=43

We move all terms to the left:

(5/4)x-(43)=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+5/4)x-43=0

We multiply parentheses

5x^2-43=0

a = 5; b = 0; c = -43;
Δ = b2-4ac
Δ = 02-4·5·(-43)
Δ = 860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{860}=\sqrt{4*215}=\sqrt{4}*\sqrt{215}=2\sqrt{215}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{215}}{2*5}=\frac{0-2\sqrt{215}}{10}
=-\frac{2\sqrt{215}}{10}
=-\frac{\sqrt{215}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{215}}{2*5}=\frac{0+2\sqrt{215}}{10}
=\frac{2\sqrt{215}}{10}
=\frac{\sqrt{215}}{5}
$