(5/4)y+y=9

Solution for (5/4)y+y=9 equation:

(5/4)y+y=9

We move all terms to the left:

(5/4)y+y-(9)=0


Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+5/4)y+y-9=0

We add all the numbers together, and all the variables

y+(+5/4)y-9=0

We multiply parentheses

5y^2+y-9=0

a = 5; b = 1; c = -9;
Δ = b2-4ac
Δ = 12-4·5·(-9)
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{181}}{2*5}=\frac{-1-\sqrt{181}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{181}}{2*5}=\frac{-1+\sqrt{181}}{10}
$