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(5/4)y=9
We move all terms to the left:
(5/4)y-(9)=0
Domain of the equation: 4)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/4)y-9=0
We multiply parentheses
5y^2-9=0
a = 5; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·5·(-9)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{5}}{2*5}=\frac{0-6\sqrt{5}}{10} =-\frac{6\sqrt{5}}{10} =-\frac{3\sqrt{5}}{5} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{5}}{2*5}=\frac{0+6\sqrt{5}}{10} =\frac{6\sqrt{5}}{10} =\frac{3\sqrt{5}}{5} $
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