(5/4x+1)-2=7/5x

Solution for (5/4x+1)-2=7/5x equation:

(5/4x+1)-2=7/5x

We move all terms to the left:

(5/4x+1)-2-(7/5x)=0


Domain of the equation: 4x+1)!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(5/4x+1)-(+7/5x)-2=0

We get rid of parentheses

5/4x-7/5x+1-2=0

We calculate fractions


25x/20x^2+(-28x)/20x^2+1-2=0

We add all the numbers together, and all the variables

25x/20x^2+(-28x)/20x^2-1=0

We multiply all the terms by the denominator


25x+(-28x)-1*20x^2=0

Wy multiply elements

-20x^2+25x+(-28x)=0

We get rid of parentheses

-20x^2+25x-28x=0

We add all the numbers together, and all the variables

-20x^2-3x=0

a = -20; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-20)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-20}=\frac{0}{-40}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-20}=\frac{6}{-40}
=-3/20
$