(5/4x+7)=(3/4x+3)

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Solution for (5/4x+7)=(3/4x+3) equation: 



(5/4x+7)=(3/4x+3)

We move all terms to the left:

(5/4x+7)-((3/4x+3))=0



Domain of the equation: 4x+7)!=0

x∈R





Domain of the equation: 4x+3))!=0

x∈R



We get rid of parentheses

5/4x-((3/4x+3))+7=0

We calculate fractions


20x/16x^2+(-((3*4x)/16x^2+7=0

We add all the numbers together, and all the variables

20x/16x^2+(-((+3*4x)/16x^2+7=0

We calculate fractions

We do not support expression: x^4

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