(5/6)x+(1/6)x=-9

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Solution for (5/6)x+(1/6)x=-9 equation: 



(5/6)x+(1/6)x=-9

We move all terms to the left:

(5/6)x+(1/6)x-(-9)=0



Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/6)x+(+1/6)x-(-9)=0

We add all the numbers together, and all the variables

(+5/6)x+(+1/6)x+9=0

We multiply parentheses

5x^2+x^2+9=0

We add all the numbers together, and all the variables

6x^2+9=0

a = 6; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·6·9
Δ = -216
Delta is less than zero, so there is no solution for the equation

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