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(5/6)x+(2/3)=(5/7)
We move all terms to the left:
(5/6)x+(2/3)-((5/7))=0
Domain of the equation: 6)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/6)x+(+2/3)-((+5/7))=0
We multiply parentheses
5x^2+(+2/3)-((+5/7))=0
We get rid of parentheses
5x^2+2/3-((+5/7))=0
We calculate fractions
5x^2+()/()+()/()=0
We add all the numbers together, and all the variables
5x^2+2=0
a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation
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