(5/6)x+4=(3/4)x+12

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Solution for (5/6)x+4=(3/4)x+12 equation: 



(5/6)x+4=(3/4)x+12

We move all terms to the left:

(5/6)x+4-((3/4)x+12)=0



Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4)x+12)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/6)x-((+3/4)x+12)+4=0

We multiply parentheses

5x^2-((+3/4)x+12)+4=0

We multiply all the terms by the denominator


5x^2*4)x+12)-((+4*4)x+12)+3=0

We add all the numbers together, and all the variables

5x^2*4)x+12)-(16x+12)+3=0

Wy multiply elements

20x^3=0

We do not support expression: x^3

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