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(5/6)x-12=2-(3/2)x
We move all terms to the left:
(5/6)x-12-(2-(3/2)x)=0
Domain of the equation: 6)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/6)x-(2-(+3/2)x)-12=0
We multiply parentheses
5x^2-(2-(+3/2)x)-12=0
We multiply all the terms by the denominator
5x^2*2)x)-(2-(-12*2)x)+3=0
We add all the numbers together, and all the variables
5x^2*2)x)-(2-(-24)x)+3=0
Wy multiply elements
10x^3-24)x)+3=0
We do not support expression: x^3
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