(5/6)y=12

Solution for (5/6)y=12 equation:

(5/6)y=12

We move all terms to the left:

(5/6)y-(12)=0


Domain of the equation: 6)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+5/6)y-12=0

We multiply parentheses

5y^2-12=0

a = 5; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·5·(-12)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*5}=\frac{0-4\sqrt{15}}{10}
=-\frac{4\sqrt{15}}{10}
=-\frac{2\sqrt{15}}{5}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*5}=\frac{0+4\sqrt{15}}{10}
=\frac{4\sqrt{15}}{10}
=\frac{2\sqrt{15}}{5}
$