(5/6c)+(3/4)=(11/12)

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Solution for (5/6c)+(3/4)=(11/12) equation: 



(5/6c)+(3/4)=(11/12)

We move all terms to the left:

(5/6c)+(3/4)-((11/12))=0



Domain of the equation: 6c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(+5/6c)+(+3/4)-((+11/12))=0

We get rid of parentheses

5/6c+3/4-((+11/12))=0

We calculate fractions


216c^2/288c^2+()/288c^2+(-((+11*6c*4)/288c^2=0

We multiply all the terms by the denominator


216c^2+(-((+11*6c*4)+()=0



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