(5/7)(t+7)=(2/7)t+23

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Solution for (5/7)(t+7)=(2/7)t+23 equation: 



(5/7)(t+7)=(2/7)t+23

We move all terms to the left:

(5/7)(t+7)-((2/7)t+23)=0



Domain of the equation: 7)(t+7)!=0

t∈R





Domain of the equation: 7)t+23)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+5/7)(t+7)-((+2/7)t+23)=0

We multiply parentheses ..

(+5t^2+5/7*7)-((+2/7)t+23)=0

We calculate fractions

We do not support etpression: t^3

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