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(5/7)t+5=(2/7)t+14
We move all terms to the left:
(5/7)t+5-((2/7)t+14)=0
Domain of the equation: 7)t!=0
t!=0/1
t!=0
t∈R
Domain of the equation: 7)t+14)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
(+5/7)t-((+2/7)t+14)+5=0
We multiply parentheses
5t^2-((+2/7)t+14)+5=0
We multiply all the terms by the denominator
5t^2*7)t+14)-((+5*7)t+14)+2=0
We add all the numbers together, and all the variables
5t^2*7)t+14)-(35t+14)+2=0
Wy multiply elements
35t^3=0
We do not support etpression: t^3
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