(5/8)(4x-16)=20

Solution for (5/8)(4x-16)=20 equation:

(5/8)(4x-16)=20

We move all terms to the left:

(5/8)(4x-16)-(20)=0


Domain of the equation: 8)(4x-16)!=0

x∈R


We add all the numbers together, and all the variables

(+5/8)(4x-16)-20=0

We multiply parentheses ..

(+20x^2+5/8*-16)-20=0

We multiply all the terms by the denominator


(+20x^2+5-20*8*-16)=0

We get rid of parentheses

20x^2+5-16-20*8*=0

We add all the numbers together, and all the variables

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$