(5/8x-12)-(1/2x-5)=0

Solution for (5/8x-12)-(1/2x-5)=0 equation:

(5/8x-12)-(1/2x-5)=0


Domain of the equation: 8x-12)!=0

x∈R



Domain of the equation: 2x-5)!=0

x∈R


We get rid of parentheses

5/8x-1/2x-12+5=0

We calculate fractions


10x/16x^2+(-8x)/16x^2-12+5=0

We add all the numbers together, and all the variables

10x/16x^2+(-8x)/16x^2-7=0

We multiply all the terms by the denominator


10x+(-8x)-7*16x^2=0

Wy multiply elements

-112x^2+10x+(-8x)=0

We get rid of parentheses

-112x^2+10x-8x=0

We add all the numbers together, and all the variables

-112x^2+2x=0

a = -112; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-112)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-112}=\frac{-4}{-224}
=1/56
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-112}=\frac{0}{-224}
=0
$