(5/9)(f-32)=-14

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Solution for (5/9)(f-32)=-14 equation:



(5/9)(f-32)=-14
We move all terms to the left:
(5/9)(f-32)-(-14)=0
Domain of the equation: 9)(f-32)!=0
f∈R
We add all the numbers together, and all the variables
(+5/9)(f-32)-(-14)=0
We add all the numbers together, and all the variables
(+5/9)(f-32)+14=0
We multiply parentheses ..
(+5f^2+5/9*-32)+14=0
We multiply all the terms by the denominator
(+5f^2+5+14*9*-32)=0
We get rid of parentheses
5f^2+5-32+14*9*=0
We add all the numbers together, and all the variables
5f^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{10}=0$

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