(5/9)(x-7)=10

Solution for (5/9)(x-7)=10 equation:

(5/9)(x-7)=10

We move all terms to the left:

(5/9)(x-7)-(10)=0


Domain of the equation: 9)(x-7)!=0

x∈R


We add all the numbers together, and all the variables

(+5/9)(x-7)-10=0

We multiply parentheses ..

(+5x^2+5/9*-7)-10=0

We multiply all the terms by the denominator


(+5x^2+5-10*9*-7)=0

We get rid of parentheses

5x^2+5-7-10*9*=0

We add all the numbers together, and all the variables

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$