(5/9)k+(2/3)=(4/3)

Solution for (5/9)k+(2/3)=(4/3) equation:

(5/9)k+(2/3)=(4/3)

We move all terms to the left:

(5/9)k+(2/3)-((4/3))=0


Domain of the equation: 9)k!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

(+5/9)k+(+2/3)-((+4/3))=0

We multiply parentheses

5k^2+(+2/3)-((+4/3))=0

We get rid of parentheses

5k^2+2/3-((+4/3))=0

We calculate fractions


5k^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{10}=0$