(5/a)-(2/1-a)=(2/a-1)

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Solution for (5/a)-(2/1-a)=(2/a-1) equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

a+5/a-(2/1) = 2/a-1 // - 2/a-1

a+5/a-(2/a)-(2/1)+1 = 0

a+5/a-2*a^-1-2+1 = 0

1*a^1+3*a^-1-1*a^0 = 0

(1*a^2-1*a^1+3*a^0)/(a^1) = 0 // * a^2

a^1*(1*a^2-1*a^1+3*a^0) = 0

a^1

a^2-a+3 = 0

a^2-a+3 = 0

DELTA = (-1)^2-(1*3*4)

DELTA = -11

DELTA < 0

a in { } 

a belongs to the empty set

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