(5/x)+(1/2x)=7

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Solution for (5/x)+(1/2x)=7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x+5/x = 7 // - 7

(1/2)*x+5/x-7 = 0

1/2*x^1+5*x^-1-7*x^0 = 0

(1/2*x^2-7*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^2-7*x^1+5*x^0) = 0

x^1

(1/2)*x^2-7*x+5 = 0

(1/2)*x^2-7*x+5 = 0

DELTA = (-7)^2-(4*5*(1/2))

DELTA = 39

DELTA > 0

x = (39^(1/2)+7)/(2*(1/2)) or x = (7-39^(1/2))/(2*(1/2))

x = 39^(1/2)+7 or x = 7-39^(1/2)

x in { 7-39^(1/2), 39^(1/2)+7} 

x in { 7-39^(1/2), 39^(1/2)+7 }

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