(5/x)+(1/3x)=(4x/3)

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Solution for (5/x)+(1/3x)=(4x/3) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*x+5/x = (4*x)/3 // - (4*x)/3

(1/3)*x-((4*x)/3)+5/x = 0

(1/3)*x+(-4/3)*x+5/x = 0

5*x^-1-1*x^1 = 0

(5*x^0-1*x^2)/(x^1) = 0 // * x^2

x^1*(5*x^0-1*x^2) = 0

x^1

5-x^2 = 0

5-x^2 = 0

DELTA = 0^2-(-1*4*5)

DELTA = 20

DELTA > 0

x = (20^(1/2)+0)/(-1*2) or x = (0-20^(1/2))/(-1*2)

x = -5^(1/2) or x = 5^(1/2)

x in { -5^(1/2), 5^(1/2)} 

x in { -5^(1/2), 5^(1/2) }

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