(5/x)-(8/(x+1)=1

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Solution for (5/x)-(8/(x+1)=1 equation: 



(5/x)-(8/(x+1)=1

We move all terms to the left:

(5/x)-(8/(x+1)-(1)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x+1)-1!=0

We move all terms containing x to the left, all other terms to the right

(x+1)!=1

x∈R



We add all the numbers together, and all the variables

(+5/x)-(8/(x+1)-1=0

We get rid of parentheses

5/x-(8/(x+1)-1=0

We calculate fractions


(5x+4)/(x^2+x-1)+(-(8*x)/(x^2+x-1)=0



We calculate terms in parentheses: +(-(8*x)/(x^2+x-1), so:

-(8*x)/(x^2+x-1

We add all the numbers together, and all the variables

-(+8x)/(x^2+x-1

We multiply all the terms by the denominator


-(+8x)

We get rid of parentheses

-8x

Back to the equation:

+(-8x)



We get rid of parentheses

(5x+4)/(x^2+x-1)-8x=0

We multiply all the terms by the denominator


(5x+4)-8x*(x^2+x-1)=0

We multiply parentheses

-8x^3-8x^2+(5x+4)+8x=0

We get rid of parentheses

-8x^3-8x^2+5x+8x+4=0

We do not support expression: x^3

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