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(5/x+3)+(4/x+2)=2
We move all terms to the left:
(5/x+3)+(4/x+2)-(2)=0
Domain of the equation: x+3)!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
5/x+4/x+3+2-2=0
We multiply all the terms by the denominator
3*x+2*x-2*x+5+4=0
We add all the numbers together, and all the variables
3x+9=0
We move all terms containing x to the left, all other terms to the right
3x=-9
x=-9/3
x=-3
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