(5/x+3)=(7/2x+3)

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Solution for (5/x+3)=(7/2x+3) equation:



(5/x+3)=(7/2x+3)
We move all terms to the left:
(5/x+3)-((7/2x+3))=0
Domain of the equation: x+3)!=0
x∈R
Domain of the equation: 2x+3))!=0
x∈R
We get rid of parentheses
5/x-((7/2x+3))+3=0
We calculate fractions
10x/2x^2+(-((7*x)/2x^2+3=0
We add all the numbers together, and all the variables
10x/2x^2+(-((+7x)/2x^2+3=0
We calculate fractions
We do not support expression: x^4

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