(5/x+5)+(2/x-5)=20/(x+5)(x-5)

Solution for (5/x+5)+(2/x-5)=20/(x+5)(x-5) equation:

(5/x+5)+(2/x-5)=20/(x+5)(x-5)

We move all terms to the left:

(5/x+5)+(2/x-5)-(20/(x+5)(x-5))=0


Domain of the equation: x+5)!=0

x∈R



Domain of the equation: x-5)!=0

x∈R



Domain of the equation: (x+5)(x-5))!=0

x∈R


We use the square of the difference formula

x^2+(5/x+5)+(2/x-5)+25=0

We get rid of parentheses

x^2+5/x+2/x+5-5+25=0

We multiply all the terms by the denominator


x^2*x+5*x-5*x+25*x+5+2=0

We add all the numbers together, and all the variables

x^2*x+25x+7=0

Wy multiply elements

x^3+25x+7=0

We do not support expression: x^3