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(5/x-3)+9=2
We move all terms to the left:
(5/x-3)+9-(2)=0
Domain of the equation: x-3)!=0We add all the numbers together, and all the variables
x∈R
(5/x-3)+7=0
We get rid of parentheses
5/x-3+7=0
We multiply all the terms by the denominator
-3*x+7*x+5=0
We add all the numbers together, and all the variables
4x+5=0
We move all terms containing x to the left, all other terms to the right
4x=-5
x=-5/4
x=-1+1/4
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