(5/x-3x)-7=-(1/2)

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Solution for (5/x-3x)-7=-(1/2) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x-(3*x)-7 = -(1/2) // + 1/2

5/x-(3*x)+1/2-7 = 0

5/x-3*x+1/2-7 = 0

5*x^-1-3*x^1-13/2*x^0 = 0

(5*x^0-3*x^2-13/2*x^1)/(x^1) = 0 // * x^2

x^1*(5*x^0-3*x^2-13/2*x^1) = 0

x^1

(-13/2)*x-3*x^2+5 = 0

(-13/2)*x-3*x^2+5 = 0

DELTA = (-13/2)^2-(-3*4*5)

DELTA = 409/4

DELTA > 0

x = ((409/4)^(1/2)-(-13/2))/(-3*2) or x = (-(-13/2)-(409/4)^(1/2))/(-3*2)

x = ((409/4)^(1/2)+13/2)/(-6) or x = (13/2-(409/4)^(1/2))/(-6)

x in { ((409/4)^(1/2)+13/2)/(-6), (13/2-(409/4)^(1/2))/(-6)}

x in { ((409/4)^(1/2)+13/2)/(-6), (13/2-(409/4)^(1/2))/(-6) }

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