(5/y)-(y/2)

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Solution for (5/y)-(y/2) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y-(y/2) = 0

5*y^-1-1/2*y^1 = 0

(5*y^0-1/2*y^2)/(y^1) = 0 // * y^2

y^1*(5*y^0-1/2*y^2) = 0

y^1

(-1/2)*y^2+5 = 0

(-1/2)*y^2+5 = 0

DELTA = 0^2-(4*5*(-1/2))

DELTA = 10

DELTA > 0

y = (10^(1/2)+0)/(2*(-1/2)) or y = (0-10^(1/2))/(2*(-1/2))

y = -10^(1/2) or y = 10^(1/2)

y in { -10^(1/2), 10^(1/2)} 

y in { -10^(1/2), 10^(1/2) }

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