(5/y+1)=(2/2y-1)

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Solution for (5/y+1)=(2/2y-1) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y+1 = (2/2)*y-1 // - (2/2)*y-1

5/y-((2/2)*y)+1+1 = 0

5/y-y+1+1 = 0

5*y^-1-1*y^1+2*y^0 = 0

(2*y^1-1*y^2+5*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^1-1*y^2+5*y^0) = 0

y^1

2*y-y^2+5 = 0

2*y-y^2+5 = 0

DELTA = 2^2-(-1*4*5)

DELTA = 24

DELTA > 0

y = (24^(1/2)-2)/(-1*2) or y = (-24^(1/2)-2)/(-1*2)

y = (2*6^(1/2)-2)/(-2) or y = (-2*6^(1/2)-2)/(-2)

y in { (2*6^(1/2)-2)/(-2), (-2*6^(1/2)-2)/(-2)} 

y in { (2*6^(1/2)-2)/(-2), (-2*6^(1/2)-2)/(-2) }

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