(50+2x)(30+2x)=0

Solution for (50+2x)(30+2x)=0 equation:

(50+2x)(30+2x)=0

We add all the numbers together, and all the variables

(2x+50)(2x+30)=0

We multiply parentheses ..

(+4x^2+60x+100x+1500)=0

We get rid of parentheses

4x^2+60x+100x+1500=0

We add all the numbers together, and all the variables

4x^2+160x+1500=0

a = 4; b = 160; c = +1500;
Δ = b2-4ac
Δ = 1602-4·4·1500
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-40}{2*4}=\frac{-200}{8}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+40}{2*4}=\frac{-120}{8}
=-15
$