(50+4x)+50+(80-2x)=180

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Solution for (50+4x)+50+(80-2x)=180 equation: 



(50+4x)+50+(80-2x)=180

We move all terms to the left:

(50+4x)+50+(80-2x)-(180)=0

We add all the numbers together, and all the variables

(4x+50)+(-2x+80)+50-180=0

We add all the numbers together, and all the variables

(4x+50)+(-2x+80)-130=0

We get rid of parentheses

4x-2x+50+80-130=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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