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(50-x)(30-x)=1125
We move all terms to the left:
(50-x)(30-x)-(1125)=0
We add all the numbers together, and all the variables
(-1x+50)(-1x+30)-1125=0
We multiply parentheses ..
(+x^2-30x-50x+1500)-1125=0
We get rid of parentheses
x^2-30x-50x+1500-1125=0
We add all the numbers together, and all the variables
x^2-80x+375=0
a = 1; b = -80; c = +375;
Δ = b2-4ac
Δ = -802-4·1·375
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-70}{2*1}=\frac{10}{2} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+70}{2*1}=\frac{150}{2} =75 $
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