(52-2x)=(10x+28)

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Solution for (52-2x)=(10x+28) equation: 



(52-2x)=(10x+28)

We move all terms to the left:

(52-2x)-((10x+28))=0

We add all the numbers together, and all the variables

(-2x+52)-((10x+28))=0

We get rid of parentheses

-2x-((10x+28))+52=0



We calculate terms in parentheses: -((10x+28)), so:

(10x+28)

We get rid of parentheses

10x+28

Back to the equation:

-(10x+28)



We get rid of parentheses

-2x-10x-28+52=0

We add all the numbers together, and all the variables

-12x+24=0

We move all terms containing x to the left, all other terms to the right

-12x=-24

x=-24/-12

x=+2

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