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(55/2)*5x-(3x-2)=5
We move all terms to the left:
(55/2)*5x-(3x-2)-(5)=0
Domain of the equation: 2)*5x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+55/2)*5x-(3x-2)-5=0
We multiply parentheses
275x^2-(3x-2)-5=0
We get rid of parentheses
275x^2-3x+2-5=0
We add all the numbers together, and all the variables
275x^2-3x-3=0
a = 275; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·275·(-3)
Δ = 3309
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{3309}}{2*275}=\frac{3-\sqrt{3309}}{550} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{3309}}{2*275}=\frac{3+\sqrt{3309}}{550} $
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