(56+2x)/9=10

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Solution for (56+2x)/9=10 equation: 



(56+2x)/9=10

We move all terms to the left:

(56+2x)/9-(10)=0

We add all the numbers together, and all the variables

(2x+56)/9-10=0

We multiply all the terms by the denominator


(2x+56)-10*9=0

We add all the numbers together, and all the variables

(2x+56)-90=0

We get rid of parentheses

2x+56-90=0

We add all the numbers together, and all the variables

2x-34=0

We move all terms containing x to the left, all other terms to the right

2x=34

x=34/2

x=17

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