(56/7w)+(4/w)=1

Solution for (56/7w)+(4/w)=1 equation:

(56/7w)+(4/w)=1

We move all terms to the left:

(56/7w)+(4/w)-(1)=0


Domain of the equation: 7w)!=0

w!=0/1

w!=0

w∈R



Domain of the equation: w)!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

(+56/7w)+(+4/w)-1=0

We get rid of parentheses

56/7w+4/w-1=0

We calculate fractions


56w/7w^2+28w/7w^2-1=0

We multiply all the terms by the denominator


56w+28w-1*7w^2=0

We add all the numbers together, and all the variables

84w-1*7w^2=0

Wy multiply elements

-7w^2+84w=0

a = -7; b = 84; c = 0;
Δ = b2-4ac
Δ = 842-4·(-7)·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-84}{2*-7}=\frac{-168}{-14}
=+12
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+84}{2*-7}=\frac{0}{-14}
=0
$