(57-7z)=2(z-3)

Solution for (57-7z)=2(z-3) equation:

(57-7z)=2(z-3)

We move all terms to the left:

(57-7z)-(2(z-3))=0

We add all the numbers together, and all the variables

(-7z+57)-(2(z-3))=0

We get rid of parentheses

-7z-(2(z-3))+57=0


We calculate terms in parentheses: -(2(z-3)), so:

2(z-3)

We multiply parentheses

2z-6

Back to the equation:

-(2z-6)


We get rid of parentheses

-7z-2z+6+57=0

We add all the numbers together, and all the variables

-9z+63=0

We move all terms containing z to the left, all other terms to the right

-9z=-63

z=-63/-9

z=+7