(5a+2)(2a+1)=0

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Solution for (5a+2)(2a+1)=0 equation:



(5a+2)(2a+1)=0
We multiply parentheses ..
(+10a^2+5a+4a+2)=0
We get rid of parentheses
10a^2+5a+4a+2=0
We add all the numbers together, and all the variables
10a^2+9a+2=0
a = 10; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·10·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*10}=\frac{-10}{20} =-1/2 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*10}=\frac{-8}{20} =-2/5 $

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