(5a+2)(a+4)=(5a+2)(a+4)=

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Solution for (5a+2)(a+4)=(5a+2)(a+4)= equation: 



(5a+2)(a+4)=(5a+2)(a+4)=

We move all terms to the left:

(5a+2)(a+4)-((5a+2)(a+4))=0

We multiply parentheses ..

(+5a^2+20a+2a+8)-((+5a^2+20a+2a+8))=0



We calculate terms in parentheses: -((+5a^2+20a+2a+8)), so:

(+5a^2+20a+2a+8)

We get rid of parentheses

5a^2+20a+2a+8

We add all the numbers together, and all the variables

5a^2+22a+8

Back to the equation:

-(5a^2+22a+8)



We get rid of parentheses

5a^2-5a^2+20a+2a-22a+8-8=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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