(5a+3b)/2=7

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Solution for (5a+3b)/2=7 equation: 


x in (-oo:+oo)

(5*a+3*b)/2 = 7 // - 7

(5*a+3*b)/2-7 = 0

(5*a+3*b)/2+(-7*2)/2 = 0

5*a+3*b-7*2 = 0

5*a+3*b-14 = 0

(5*a+3*b-14)/2 = 0

(5*a+3*b-14)/2 = 0 // * 2

5*a+3*b-14 = 0

x belongs to the empty set

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