(5a-2)(3a+4)=(3a-5)(5a+1)+15

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Solution for (5a-2)(3a+4)=(3a-5)(5a+1)+15 equation:



(5a-2)(3a+4)=(3a-5)(5a+1)+15
We move all terms to the left:
(5a-2)(3a+4)-((3a-5)(5a+1)+15)=0
We multiply parentheses ..
(+15a^2+20a-6a-8)-((3a-5)(5a+1)+15)=0
We calculate terms in parentheses: -((3a-5)(5a+1)+15), so:
(3a-5)(5a+1)+15
We multiply parentheses ..
(+15a^2+3a-25a-5)+15
We get rid of parentheses
15a^2+3a-25a-5+15
We add all the numbers together, and all the variables
15a^2-22a+10
Back to the equation:
-(15a^2-22a+10)
We get rid of parentheses
15a^2-15a^2+20a-6a+22a-8-10=0
We add all the numbers together, and all the variables
36a-18=0
We move all terms containing a to the left, all other terms to the right
36a=18
a=18/36
a=1/2

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