(5a-2)+(7a-5)=7-(14-11a)

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Solution for (5a-2)+(7a-5)=7-(14-11a) equation: 



(5a-2)+(7a-5)=7-(14-11a)

We move all terms to the left:

(5a-2)+(7a-5)-(7-(14-11a))=0

We add all the numbers together, and all the variables

(5a-2)+(7a-5)-(7-(-11a+14))=0

We get rid of parentheses

5a+7a-(7-(-11a+14))-2-5=0



We calculate terms in parentheses: -(7-(-11a+14)), so:

7-(-11a+14)

determiningTheFunctionDomain
-(-11a+14)+7

We get rid of parentheses

11a-14+7

We add all the numbers together, and all the variables

11a-7

Back to the equation:

-(11a-7)



We add all the numbers together, and all the variables

12a-(11a-7)-7=0

We get rid of parentheses

12a-11a+7-7=0

We add all the numbers together, and all the variables

a=0

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